University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 5 - Applying Newton's Laws - Problems - Exercises - Page 168: 5.98

Answer

The radius of the circle is 18.6 meters.

Work Step by Step

We can find Jack's speed $v$. $v = (0.100~rev/s)(\frac{2\pi ~r~m}{1~rev})$ $v = (0.2\pi ~r)~m/s$ We can find the radius of the circle. $\sum F = \frac{mv^2}{r}$ $mg - F_N = \frac{m~(0.2\pi ~r)^2}{r}$ $mg - 0.25~mg = {m~(0.2\pi)^2~r}$ $0.75~g = {(0.2\pi)^2~r}$ $r = \frac{0.75~g}{(0.2\pi)^2}$ $r = 18.6~m$ The radius of the circle is 18.6 meters.
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