#### Answer

(a) The minimum radius is 230 meters.
(b) The pilot's apparent weight is 2450 N.

#### Work Step by Step

(a) Let's suppose the centripetal acceleration is 4.00 g.
$4.00~g = \frac{v^2}{r}$
$r = \frac{v^2}{4.00~g} = \frac{(95.0~m/s)^2}{(4.00)(9.80~m/s^2)}$
$r = 230~m$
The minimum radius is 230 meters.
(b) $\sum F = \frac{mv^2}{r}$
$F_N-mg = \frac{mv^2}{r}$
$F_N = \frac{mv^2}{r} + mg$
$F_N = \frac{(50.0~kg)(95.0~m/s)^2}{230~m} + (50.0~kg)(9.80~m/s^2)$
$F_N = 2450~N$
The pilot's apparent weight is 2450 N.
(Note that this apparent weight is equal to 5 times the pilot's usual weight.)