## University Physics with Modern Physics (14th Edition)

(a) Let $m_b$ be the mass of the ball. Let $m_c$ be the mass of the chain. The minimum tension in the chain is just above the wrecking ball. $T = (m_b)~g = (75.0~kg)(9.80~m/s^2) = 735~N$ The maximum tension in the chain is at the top of the chain. $T = (m_b+m_c)g = (75.0~kg+ 26.0~kg)(9.80~m/s^2) = 990~N$ (b) We can find the tension 3/4th of the way up the chain. $T = (m_b+0.75\times m_c)g = (75.0~kg+ 19.5~kg)(9.80~m/s^2) = 926~N$