Answer
Since the total initial mass is smaller than the total final mass, additional energy has to be provided as kinetic energy of the proton to make this reaction happen.
The answer is option $(d)$
Work Step by Step
The reaction that produce ${^{123}_{53}I}$ is given by
${^{123}_{52}Te}+p \rightarrow {^{123}_{53}I}+n$
To know whether the proton needs a minimum kinetic energy, we must first find out the reaction energy.
The reaction energy is given by
$Q=\Delta mc^{2}$
where $\Delta m$ is the mass difference between the initial and final products.
In our case
$Q=(M_{Te}+M_{p}-M_{I}-M_{n})c^{2}$
substituting the values, we get
$Q=(122.904270+1.007825-122.905589-1.008665)\times uc^{2}$
$Q=-0.002159\times uc^{2}$
Since Q is negative, the reaction is an endoergic reaction. Therefore, additional energy has to be provided as kinetic energy of the proton to make this reaction happen.
