Answer
Choice B.
Work Step by Step
$L=\sqrt{l(l+1)}\hbar$
Here, $l=2$.
$L=\sqrt{2(3)}\hbar=\sqrt{6}\hbar $
Note that in other states, L could be much larger since $l$ could be as large as n-1=99.
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 41 - Quantum Mechanics II: Atomic Structure - Problems - Exercises - Page 1406: 41.72
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
