## University Physics with Modern Physics (14th Edition)

The energy levels are given by $E_n=(n+\frac{1}{2})\hbar\omega$. The ground state energy is when n=0. The energy difference between any two states is 11.2 eV, which is twice the ground state energy of 5.60 eV. Find the wavelength. $$\lambda =\frac{hc}{\Delta E}$$ $$\lambda =\frac{1.24\times10^{-6}eV\cdot m}{11.2eV }=1.11\times10^{-7}m$$