University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 40 - Quantum Mechanics I: Wave Functions - Problems - Exercises - Page 1355: 40.37


111 nm.

Work Step by Step

The energy levels are given by $E_n=(n+\frac{1}{2})\hbar\omega$. The ground state energy is when n=0. The energy difference between any two states is 11.2 eV, which is twice the ground state energy of 5.60 eV. Find the wavelength. $$\lambda =\frac{hc}{\Delta E}$$ $$\lambda =\frac{1.24\times10^{-6}eV\cdot m}{11.2eV }=1.11\times10^{-7}m $$
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