Answer
825 N, exerted by the blocks.
Work Step by Step
Apply Newton’s second law.
$\Sigma F_x=ma_x$
$=(55kg)(15m/s^2)=825N$
This force is exerted by the blocks on the sprinter. It is the reaction force to the sprinter pushing on the blocks.
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 4 - Newton's Laws of Motion - Problems - Exercises - Page 125: 4.21
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