University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 39 - Particles Behaving as Waves - Problems - Exercises - Page 1313: 39.3

Answer

See explanation.

Work Step by Step

a. $p=\frac{h}{\lambda}=\frac{6.626\times10^{-34}J \cdot s}{2.80\times10^{-10}m}=2.37\times10^{-24}kg \cdot m/s$ b. $K=\frac{p^2}{2m}=\frac{(2.37\times10^{-24}kg \cdot m/s)^2}{2(9.11\times10^{-31}kg)}=3.08\times10^{-18}J=19.3 eV$
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