Answer
We use the relativistic form of Newton’s second law.
$F=2.04\times10^{-13}N $.
Work Step by Step
According to equation 37.33, in this situation where force and velocity are perpendicular, the force is $F=\gamma ma=\gamma m \frac{v^2}{R}$.
$\gamma=\frac{1}{\sqrt{1-v^{2}/c^{2}}}=1.512$
$$F=(1.512)(1.67\times10^{-27}kg) \frac{((0.750)(3.00\times10^8m/s))^2}{628m}$$
$$F=2.04\times10^{-13}N $$
