University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 37 - Relativity - Problems - Exercises - Page 1250: 37.54

Answer

It is a proton.

Work Step by Step

Use the relativistic formula for momentum, $p=\frac{mv}{\sqrt{1-v^2/c^2}}$. Solve for $m=\frac{p\sqrt{1-v^2/c^2}}{v}=1.67\times10^{-27}kg$. A positively charged particle with this mass must be a proton.
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