Answer
See explanation.
Work Step by Step
a. The interval, measured on Mars, is the proper time $\Delta t_o$. The on/off events are at rest there.
b. The value of $\gamma$ is $\frac{1}{\sqrt{1-u^{2}/c^{2}}}=5.795$.
The pilot measures a dilated time interval of $\gamma \Delta t_o =4.35\times10^{-4}s$.
