University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 36 - Diffraction - Problems - Exercises - Page 1212: 36.9

Answer

$\theta = \pm 16.0^{\circ}, \pm 33.4^{\circ}, \pm 55.6^{\circ}$.

Work Step by Step

The silent points are located at angles that satisfy $sin \theta=\frac{m \lambda}{a}$, where $m=\pm 1, \pm 2…$. The wavelength $\lambda=\frac{v}{f}=\frac{344m/s}{1250Hz}=0.2752 m$. Find the first angle. $$sin \theta_1=\frac{\lambda}{a}$$ $$\theta_1 = sin^{-1}(\frac{0.2752 m }{1.00m})=16.0^{\circ}$$ Find the second angle. $$sin \theta_2=\frac{2 \lambda}{a}$$ $$\theta_2 = sin^{-1}(2 \frac{0.2752 m }{1.00m})=33.4^{\circ}$$ Find the third angle. $$sin \theta_3=\frac{3 \lambda}{a}$$ $$\theta_3 = sin^{-1}(3 \frac{0.2752 m }{1.00m})=55.6^{\circ}$$ Someone at these angles, on either side of the centerline, will hear no sound. There are no other real solutions for m = 4, 5, etc.
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