University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 36 - Diffraction - Problems - Discussion Questions - Page 1211: Q36.11

Answer

The shorter wavelength has a narrower central fringe.

Work Step by Step

As shown by equation 36.2, for a shorter wavelength $\lambda$, the angle $\theta$ is smaller, which corresponds to a tighter beam. This can be used with smaller pits on the disc, which allows more data to be stored on a Blu-Ray formatted disc.
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