## University Physics with Modern Physics (14th Edition)

Apply the thin-lens formula. We are told that a lens with $\frac{1}{f}=-6.0D$ would correct the frog’s distance vision. This lens would take an object at infinity and create a virtual image at the near point. $$\frac{1}{s}+\frac{1}{s’}=\frac{1}{f}$$ $$\frac{1}{\infty}+\frac{1}{s’}=-6.0m^{-1}$$ $$s’=-0.17m$$ The frog can clearly see an object that is 17cm away.