University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 31 - Alternating Current - Problems - Exercises - Page 1044: 31.7



Work Step by Step

$X_C=\frac{V}{I}=\frac{170V}{0.850A}=200\Omega$ Solve $X_C=\frac{1}{2 \pi fC}$ for the capacitance. $C=\frac{1}{2 \pi fX_C}=\frac{1}{2 \pi (60.0Hz)( 200\Omega)}=1.33\times10^{-5}F$
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