Answer
The pilot should release the canister a horizontal distance of 274 meters from the target.
Work Step by Step
We can find the time $t$ it takes to reach the ground.
$y = \frac{1}{2}gt^2$
$t = \sqrt{\frac{2y}{g}} = \sqrt{\frac{(2)(90.0~m)}{9.80~m/s^2}}$
$t = 4.286~s$
We can find the horizontal distance $x$.
$x = v_x~t = (64.0~m/s)(4.286~s) = ~m$
$x = 274~m$
The pilot should release the canister a horizontal distance of 274 meters from the target.
