Answer
$a_R = 24.9~m/s^2$
$a_R = 2.54~g$
Work Step by Step
$v = (3.0~rev/s)(2\pi\cdot 0.070~m/rev) = 0.42~\pi~m/s$
$a_R = \frac{v^2}{r} = \frac{(0.42\pi~m/s)^2}{0.070~m}$
$a_R = 24.9~m/s^2$
$a_R = \frac{24.9~m/s^2}{9.80~m/s^2}g = 2.54~g$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 3 - Motion in Two or Three Dimensions - Problems - Exercises - Page 94: 3.24
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