University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 3 - Motion in Two or Three Dimensions - Problems - Exercises - Page 93: 3.2

Answer

(a) x = -45.6 meters y = 58.8 meters (b) The rhinoceros is 74.41 meters from the origin.

Work Step by Step

At $t_1 = 0$, the coordinates of the rhinoceros are (0,0). (a) At $t_2 = 12.0 s$: $v_{av,x} = \frac{\Delta x}{\Delta t} = \frac{x-0}{12.0~s} = -3.8~m/s$ $x = (12.0~m/s)(-3.8~m/s) = -45.6~m$ $v_{av,y} = \frac{\Delta y}{\Delta t} = \frac{y-0}{12.0~s} = 4.9~m/s$ $y = (4.9~m/s)(12.0~s) = 58.8~m$ (b) We can find the distance $d$ from the origin. $d = \sqrt{x^2+y^2}$ $d = \sqrt{(-45.6~m)^2+(58.8~m)^2}$ $d = 75~m$ The rhinoceros is 74.41 meters from the origin.
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