Answer
a. 2.81 mV/m.
b. counterclockwise.
Work Step by Step
The magnitude of the induced electric field is given by Faraday’s Law.
$$E(2 \pi r)=\frac{d}{dt}(B\pi r^2)= \pi r^2\frac{dB}{dt}$$
$$E=\frac{r}{2}\frac{dB}{dt}$$
$$E=\frac{0.0225m}{2}(0.250T/s)=2.81mV/m$$
b. The field points toward the viewer (on the magnetic south pole) and it is decreasing. The induced current makes a field that is directed toward the viewer, to help out the decreasing field strength.
By the right hand rule, the induced current is counterclockwise.
