Answer
See explanation.
Work Step by Step
The change in magnetic flux induces an emf.
a. $$|\epsilon|=|\frac{d \Phi_B}{dt}|=\frac{d}{dt}(A(B_0+bx))=bA\frac{dx}{dt}=bAv$$
b. Clockwise
c. The emf is the same, but the current is counterclockwise.