Answer
(a) $Q_1 =156 \mathrm{~\mu C}$ and $Q_2 = 260 \mathrm{~\mu C}$
(b) $V_1 = V_2 = 52 \,\text{V}$
Work Step by Step
(a) As both capacitors are in parallel, therefore, they have the same potential even they have different capacitances. So the charge for each capacitor is calculated as next:
For $C_1$
$$Q_1 = C_1 V = (3\mathrm{~\mu F} ) (52 \,\text{V}) = \boxed{156 \mathrm{~\mu C}}$$
For $C_2$
$$Q_2 = C_2 V = (5\mathrm{~\mu F} ) (52 \,\text{V}) = \boxed{260 \mathrm{~\mu C}}$$
(b) In parallel, the combination of the two capacitors has the same potential for each capacitor
$$\boxed{V_1 = V_2 = 52 \,\text{V}}$$
