University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 24 - Capacitance and Dielectrics - Problems - Exercises - Page 809: 24.4

Answer

$C = 1.59 \times 10^{-12} \,\text{F}$

Work Step by Step

The capacitance depends on the area $A$ of the plate and the distance between the two plates and it is given by $$C = \dfrac{\epsilon_o A}{d}$$ Substitute by the values of $\epsilon_o, A$ and $d$ to get the capacitance $c$ \begin{align*} C &= \dfrac{\epsilon_o A}{d} = \dfrac{(8.85 \times 10^{-12} \,\text{F/m}) (0.030\,\text{m})^2}{0.05 \,\text{m}} = \boxed{1.59 \times 10^{-12} \,\text{F}} \end{align*}
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