University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 24 - Capacitance and Dielectrics - Problems - Discussion Questions - Page 808: Q24.21

Answer

The electric field decreases.

Work Step by Step

Equation 24.14 shows that the electric field strength in the presence of a dielectric, when charge is constant, is reduced by a factor of $\kappa$. The field can be measured by measuring the potential difference V between the plates, and knowing the plate separation d. $E=\frac{V}{d}$.
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