University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 2 - Motion Along a Straight Line - Problems - Exercises - Page 63: 2.71

Answer

(a) The maximum height on Mars is $2.64 \times H$ (b) The time in the air on Mars is $2.64 \times T$

Work Step by Step

(a) The acceleration of gravity on Mars is $\frac{3.71}{9.80}\times g = 0.3786~g$ On Earth: $H = \frac{v_0^2}{2g}$ On Mars: $H_M = \frac{v_0^2}{(2)(0.3786~g)} = 2.64 \times \frac{v_0^2}{2g}$ $H_M = 2.64 \times H$ The maximum height on Mars is $2.64 \times H$ (b) On Earth: $T = 2\times \frac{v_0}{g}$ On Mars: $T_M = 2\times \frac{v_0}{0.3786~g} = 2.64\times (2\times \frac{v_0}{g})$ $T_M = 2.64\times T$ The time in the air on Mars is $2.64 \times T$
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