#### Answer

From a height of $3h$, it would take a time of $\sqrt{3} ~T$ to reach the ground.

#### Work Step by Step

Let $h$ be the height where it was dropped originally.
$h = \frac{1}{2}gT^2$
$T = \sqrt{\frac{2h}{g}}$
Now suppose the object is dropped from a height of $3h$.
$3h = \frac{1}{2}gt_2^2$
$t_2 = \sqrt{\frac{6h}{g}}$
$t_2 = \sqrt{3}\times \sqrt{\frac{2h}{g}} = \sqrt{3} ~T$
From a height of $3h$, it would take a time of $\sqrt{3} ~T$ to reach the ground.