University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 19 - The First Law of Thermodynamics - Problems - Exercises - Page 641: 19.20

Answer

$\Delta U = 360 J $

Work Step by Step

This is a constant pressure process, so the change in internal energy is $\Delta U = \frac{3}{2} p( V_f - V_i) $ $\Delta U = \frac{3}{2} (4.0 \times 10^4 Pa) ( 8.00 \times 10^{-3} m^3 - 2.00 \times 10^{-3} m^3) $ $\Delta U = 360 J $
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