University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 18 - Thermal Properties of Matter - Problems - Exercises - Page 610: 18.3

Answer

0.1 atm.

Work Step by Step

From the ideal gas law, $pV = nRT$. In this case, $nRT$ is constant, so we have $p_1 V_1 = p_2 V_2$. $p_2 = p_1 (\frac{V_1}{V_2}) = (0.355)(\frac{0.11}{0.39}) = 0.1 \ atm$.
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