University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 15 - Mechanical Waves - Problems - Exercises - Page 497: 15.1

Answer

(a) $\lambda = 0.439~m$ $T = 1.28~ms$ (b) $\lambda = 0.219~m$

Work Step by Step

(a) We can find the wavelength. $\lambda~f = v$ $\lambda = \frac{v}{f}$ $\lambda = \frac{344~m/s}{784~Hz}$ $\lambda = 0.439~m$ We can find the period of oscillation. $T = \frac{1}{f}$ $T = \frac{1}{784~Hz}$ $T = 0.00128~s = 1.28~ms$ (b) If the sound wave is one octave higher, the frequency is 1568 Hz. We can find the wavelength. $\lambda~f = v$ $\lambda = \frac{v}{f}$ $\lambda = \frac{344~m/s}{1568~Hz}$ $\lambda = 0.219~m$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.