#### Answer

Since the weight is only 41.9 N, we should be able to deliver the iron rod without a cart.

#### Work Step by Step

We can find the volume of the rod.
$V = \pi~r^2~h$
$V = (\pi)(0.01425~m)^2(0.858~m)$
$V = 5.47\times 10^{-4}~m^3$
We can find the mass of the rod.
$M = \rho~V$
$M = (7800~kg/m^3)(5.47\times 10^{-4}~m^3)$
$M = 4.27~kg$
We can find the weight of the rod.
$weight = (4.27~kg)(9.80~m/s^2) = 41.9~N$
Since the weight is only 41.9 N, we should be able to deliver the iron rod without a cart.