University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 11 - Equilibrium and Elasticity - Problems - Exercises - Page 363: 11.62

Answer

$$T_{E}=0.833 N$$ $$T_{F}=0.931 N$$

Work Step by Step

$W_{r}=(0.12)(9.8)=1.176 N$ $T_{A}=(0.036)(9.8)=0.353 N$ $T_{B}=(0.036+0.024)(9.8)=0.588 N$ $T_{C}=T_{B}cos(53.1)=(0.588)cos(53.1)=0.353 N$ $T_{D}=T_{B}cos(36.9)=(0.588)cos(36.9)=0.47 N$ $\tau = (T_{E})(1m)-(0.8m)T_{D}sin(36.9)-(0.2)T_{C}sin(53.1)-(W_{r})(0.5m)$ $T_{E}=(0.8)(0.47)sin(36.9)+(0.2)(0.353)sin(53.1)+(0.5)(0.12)(9.8)=0.833 N$ $\Sigma F_{y}=T_{E}+T_{F}-(W_{Y}+W_{A}+W_{B})(9.8)=0$ $T_{F}=(0.12+0.036+0.024)(9.8)-(0.833)=0.931 N$
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