## University Physics with Modern Physics (14th Edition)

Let $L$ be Lancelot's distance from the castle end of the bridge. Let's assume that the tension $T$ in the cable is at its maximum. We can find Lancelot's position when the net torque about the castle end of the bridge is zero. $\sum \tau = 0$ $(600~kg)(g)~L+(200~kg)(g)(6.0~m) - (5.80\times 10^3~N)(12.0~m) = 0$ $(600~kg)(g)~L = (5.80\times 10^3~N)(12.0~m) -(200~kg)(g)(6.0~m)$ $L = \frac{(5.80\times 10^3~N)(12.0~m) -(200~kg)(9.80~m/s^2)(6.0~m)}{(600~kg)(9.80~m/s^2)}$ $L = 9.84~m$ When Lancelot is 9.84 meters from the castle end of the bridge, the tension in the cable is at its maximum and it will break.