Answer
$Y = 20\times 10^{10}~Pa$
Work Step by Step
We can find the Young's modulus for this metal.
$Y = \frac{F~L_0}{A~\Delta L}$
$Y = \frac{(5000~N)(4.00~m)}{(0.50\times 10^{-4}~m^2)(0.20\times 10^{-2}~m)}$
$Y = 20\times 10^{10}~Pa$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 11 - Equilibrium and Elasticity - Problems - Exercises - Page 359: 11.27
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