University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 10 - Dynamics of Rotational Motion - Problems - Exercises - Page 331: 10.41

Answer

The angular speed of the neutron star is 4600 rad/s.

Work Step by Step

We can use conservation of angular momentum to solve this question. $L_2 = L_1$ $I_2\omega_2 = I_1\omega_1$ $(\frac{2}{5}mR_2^2)\omega_2=(\frac{2}{5}mR_1^2)\omega_1$ $\omega_2 = (\frac{R_1}{R_2})^2~\omega_1$ $\omega_2 = (\frac{7.0\times 10^5~km}{16~km})^2~[\frac{2\pi~rad}{(30~days)(24~hr/day)(3600~s/hr)}]$ $\omega_2 = 4600~rad/s$ The angular speed of the neutron star is 4600 rad/s.
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