University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 10 - Dynamics of Rotational Motion - Problems - Discussion Questions - Page 328: Q10.11

Answer

See explanation.

Work Step by Step

Gravity acts on the baton at its center of mass. When calculating the torque of the gravitational force around the center of mass, $\vec{\tau}=\vec{r} \times \vec{F}$, the distance r is zero. There is no torque about the baton's center of mass, so there is no angular acceleration, and the angular velocity stays constant.
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