Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 7 - Entropy - Problems - Page 413: 7-185

Answer

It is valid.

Work Step by Step

For the isentropic process: $T_{2s}=T_1\left(\dfrac{P_2}{P_1}\right)^{(k-1)/k}$ Given $T_1=573\ K,\ P_2=100\ kPa,\ P_1=1200\ kPa,\ k=1.395$: $T_{2s}=283.5\ K$ From the energy balance: $\dot{W}_s=-\dot{m}\Delta h = -\dot{m}c_p(T_{2s}-T_1)$ With $\dot{m}=1\ kg/s,\ c_p=1.013\ kJ/kg.K$ $\dot{W}_s=293\ kW$ Since this is greater than the power claimed by the inventor, the claim is valid.
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