Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 7 - Entropy - Problems - Page 411: 7-170

Answer

a) $\Delta S_{total}=0.000173\ kJ/K$ $\Delta S\geq 0 \rightarrow\mbox{possible}$ b) $\Delta S_{total}=-0.000101\ kJ/K$ $\Delta S\lt0 \rightarrow\mbox{impossible}$

Work Step by Step

Given: $Q_L=1\ kJ,\ T_H=303\ K,\ T_L=253\ K$ With $COP=4$: $Q_H=Q_L(1+1/COP)=1.25\ kJ$ $\Delta S_{total}=\dfrac{Q_H}{T_H}-\dfrac{Q_L}{T_L}$ $\Delta S_{total}=0.000173\ kJ/K$ $\Delta S\geq 0 \rightarrow\mbox{possible}$ With $COP=6$: $Q_H=Q_L(1+1/COP)=1.167\ kJ$ $\Delta S_{total}=\dfrac{Q_H}{T_H}-\dfrac{Q_L}{T_L}$ $\Delta S_{total}=-0.000101\ kJ/K$ $\Delta S\lt0 \rightarrow\mbox{impossible}$
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