Answer
$q=515\ Btu/lbm$
Work Step by Step
$q=\int Tds$
For 1-2:
$q_{1-2}=\frac{(T_1+T_2)}2(s_2-s_1)$
For 2-3:
$q_{2-3}=T_2(s_3-s_2)$
Given $T_1=515°R,\ T_2=T_3=820°R$
$s_1=1\ Btu/lbm.°R,\ s_2=3s_1,\ s_3=2s_1$
$q=515\ Btu/lbm$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 7 - Entropy - Problems - Page 400: 7-45E
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