## Thermodynamics: An Engineering Approach 8th Edition

a) $Q=-388.5Btu$ b) $\Delta S=0.7\ Btu/°R$ c) $S_{gen}=0$
For the fluid: $\Delta S=\frac{Q}{T}$ $\Delta S=-0.7\ Btu/°R,\ T=555°R$ $Q=-388.5Btu$ For the sink: $\Delta S=\frac{Q}{T}$ $Q_s=-Q_f,\ T_s=T_f$ $\Delta S=0.7\ Btu/°R$ $S_{gen}=\Delta S_f+\Delta S_s$ $S_{gen}=0$