Answer
a) $Q=-388.5Btu$
b) $\Delta S=0.7\ Btu/°R$
c) $S_{gen}=0$
Work Step by Step
For the fluid:
$\Delta S=\frac{Q}{T}$
$\Delta S=-0.7\ Btu/°R,\ T=555°R$
$Q=-388.5Btu$
For the sink:
$\Delta S=\frac{Q}{T}$
$Q_s=-Q_f,\ T_s=T_f$
$\Delta S=0.7\ Btu/°R$
$S_{gen}=\Delta S_f+\Delta S_s$
$S_{gen}=0$
