Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 325: 6-150

Answer

a) $\dot{Q}_H=55.73\ kW$ b) $\dot{W}_{i,min}=5.52\ kW$

Work Step by Step

$\dot{m}=\dot{V}/v,\quad\dot{V}=0.02m³/min,\ v=0.001\ m³/kg$ $\dot{m}=0.33\ kg/s$ $\dot{Q}_H=\dot{m}c_p\Delta T,\ c_p=4.18\ kJ/kg.K,\ \Delta T=(50-10)°C$ $\dot{Q}_H=55.73\ kW$ $COP_{HP, max}=\dfrac{1}{1-\frac{T_L}{T_H}}$ $T_L=0°C,\ T_H=30°C$ $COP=10.1$ $COP_{HP,max}=\dot{Q}_H/\dot{W}_{i,min}$ $\dot{W}_{i,min}=5.52\ kW$
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