Answer
$\eta_{max}=0.291=29.1\%$
Work Step by Step
$\eta_{max}=1-\dfrac{T_L}{T_H}$
Given $T_L=293 K,\ T_H=413\ K$
$\eta_{max}=0.291=29.1\%$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 6 - The Second Law of Thermodynamics - Problems - Page 318: 6-83
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