Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 6 - The Second Law of Thermodynamics - Problems - Page 314: 6-37C

Answer

See answer below.

Work Step by Step

The Kelvin–Planck definition says that it's impossible for there to be adevice that converts 100% of the input input energy into work, since some heat will always be lost to the environment (friction, faulty insulation, etc.) The Clausius definition says that's not possible to create a device that only transfer heat from a colder source to a warmer one, requiring input energy to work. For a cycle that violates the first definition $W_e=Q_H$, and uses this work in a refrigerator, rejecting $Q_H+Q_L$ to the hot reservoir, would be a violation of the second definition too, hence they are equivalent.
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