Answer
$Q_i=72.8\ kJ$
Work Step by Step
Initial specific volume:
$v=V/m,\ V=0.0015\ m^3,\ m_1=0.55\ kg$
$v_1=0.002727\ m^3/kg$
At ($T_1=26°C,\ v_1$): $x_1=0.06499,\ u_1=97.45\ kJ/kg,\ h_e=264.73\ kJ/kg$
$m_2=0.15\ kg \rightarrow v_2=0.01\ m³/kg$
At ($T_2=26°C,\ v_2$): $x_2=0.3143,\ u_2=136.56\ kJ/kg$
$-m_e=m_2-m_1$
$m_e=0.4\ kg$
$Q_i-m_eh_e=m_2u_2-m_1u_1$
$Q_i=72.8\ kJ$