Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 270: 5-178

Answer

$Q_i=72.8\ kJ$

Work Step by Step

Initial specific volume: $v=V/m,\ V=0.0015\ m^3,\ m_1=0.55\ kg$ $v_1=0.002727\ m^3/kg$ At ($T_1=26°C,\ v_1$): $x_1=0.06499,\ u_1=97.45\ kJ/kg,\ h_e=264.73\ kJ/kg$ $m_2=0.15\ kg \rightarrow v_2=0.01\ m³/kg$ At ($T_2=26°C,\ v_2$): $x_2=0.3143,\ u_2=136.56\ kJ/kg$ $-m_e=m_2-m_1$ $m_e=0.4\ kg$ $Q_i-m_eh_e=m_2u_2-m_1u_1$ $Q_i=72.8\ kJ$
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