Answer
$\dot{m}=0.1196\ kg/s=3.772\times10^6\ kg/year$
Work Step by Step
From the energy balance:
$\dot{Q}+\dot{m}h_1=\dot{m}h_2$
$\dot{Q}=\dot{m}c_p\Delta T$
Given $\dot{Q}=4kW,\ c_p=4.18\ kJ/kg.K,\ \Delta T=4°C$
$\dot{m}=0.1196\ kg/s=3.772\times10^6\ kg/year$