Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 260: 5-93

Answer

$\dot{m}=0.1196\ kg/s=3.772\times10^6\ kg/year$

Work Step by Step

From the energy balance: $\dot{Q}+\dot{m}h_1=\dot{m}h_2$ $\dot{Q}=\dot{m}c_p\Delta T$ Given $\dot{Q}=4kW,\ c_p=4.18\ kJ/kg.K,\ \Delta T=4°C$ $\dot{m}=0.1196\ kg/s=3.772\times10^6\ kg/year$
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