Chapter 5 - Mass and Energy Analysis of Control Volumes - Problems - Page 259: 5-86

$\dot{m}_s=1.60\ kg/s$

For the water ($c_p=4.18\ kJ/kg.K,\ T_2=27°C,\ T_1=18°C,\ \dot{m}_w=101\ kg/s$): $\dot{Q}=\dot{m}_wc_p(T_2-T_1)$ $\dot{Q}=3800\ kJ/s$ For the steam ($\Delta h_v=2382.0\ kJ/kg$): $\dot{Q}=\dot{m}_s\Delta h_v$ $\dot{m}_s=1.60\ kg/s$