Answer
$W = 12.87\ kJ$
Work Step by Step
Given the polytropic process with $n = 1.5$:
$P_1V_1^n=P_2V_2^n$
Given the values:
$P_1 = 350kPa,\ V_1 = 0.03\ m³,\ V_2 = 0.2\ m³$
We can calculate $P_2$ to be:
$P_2 = 20.33\ kPa$
For a polytropic process, work is given by:
$W = \frac{P_2V_2-P_1V_1}{1-n}$
$W = 12.87\ kJ$
