Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 3 - Properties of Pure Substances - Problems - Page 160: 3-128

Answer

The sketches are shown at the image

Work Step by Step

$P_{1}=300kPa$ $\upsilon_{1}=0.5\frac{m^3}{kg}$ As $0.001073\frac{m^3}{kg}\lt \upsilon\lt 0.60582\frac{m^3}{kg}$ is a saturated mixture From table A-5: $T_{1}=133.52^{\circ}C$ $P_{2}=300kPa$ $x_{2}=1$ $T_{2}=133.52^{\circ}C$ From table A-5: $\upsilon_{2}=0.60582\frac{m^3}{kg}$ $P_{3}=600kPa$ $\upsilon_{3}=0.60582\frac{m^3}{kg}$ As $\upsilon_{3}\gt \upsilon_{g}$ is a superheated vapor Interpolating from table A-6: $T_{3}=517.77^{\circ}C$
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