Answer
c) $0.574\frac{kJ}{s}$
Work Step by Step
The rate of energy supply is:
$E=\frac{0.50hp*0.746\frac{kJ}{s}}{0.65}=0.574\frac{kJ}{s}$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 107: 2-125
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