Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 11 - Refrigeration Cycles - Problems - Page 647: 11-84

Answer

$\mathrm{COP}_{\mathrm{R}, \max }=2.64$

Work Step by Step

The maximum COP that this refrigeration system can have is $$ \mathrm{COP}_{\mathrm{R}, \max }=\left(1-\frac{T_0}{T_s}\right)\left(\frac{T_L}{T_0-T_L}\right)=\left(1-\frac{298 \mathrm{~K}}{393 \mathrm{~K}}\right)\left(\frac{273}{298-273}\right)=\mathbf{2 . 6 4} $$
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