Thermodynamics: An Engineering Approach 8th Edition

Published by McGraw-Hill Education
ISBN 10: 0-07339-817-9
ISBN 13: 978-0-07339-817-4

Chapter 1 - Introduction and Basic Concepts - Problems - Page 42: 1-16

Answer

$ t (in s) = \frac{V}{v} $

Work Step by Step

Assuming the tank was empty and denoting V as the volume of the tank in L and v as the discharge rate of gasoline in L/s: $ t(s) = V(L) \times \frac{1}{v(\frac{L}{s})} $ In units: $ s = L \times \frac{s}{L} $ Hence the time it would take is $ t (in s) = \frac{V}{v} $ P.S. If the tank has an initial volume $V_{0}$, the time it would take is $ t (in s) = \frac{V - V_{0}}{v} $.
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