Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 213: 50

Answer

(a) $2.3\times 10^6J$ (b) $2$

Work Step by Step

(a) We can find the required energy as $P=\frac{W}{t}$ This can be rearranged as: $W=Pt$ We plug in the known values to obtain: $W=(0.30hp\times 746W/hp)(2h\times 3600s/h+49min\times 60s/min)$ $W=2.3\times 10^6J$ (b) We can find the required number of snickers candy bars as follows: $2.3\times 10^6\times \frac{1Cal}{4186J}\times \frac{1\space snickers \space candy\space bars}{280cal}=1.9$ That is, 2 snickers candy bars.
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